V=22.7n or n=V/22.7 If you want to use this, you can, or (as I prefer, but entirely up to you) you can use the ratio idea. Both methods use the same way to initially find n, so that is still important. You may …

The molarity of the acid is 1.434. Start with the equation: 2H N O3(aq) +Ca(OH)2(aq) → Ca(N O3)2(aq) +2H 2O(l) This tells us that 2 moles of H N O3 reacts with 1 mole of Ca(OH)2 c = n v So n = cv So …

pH = 0,52 4 g of calcium Hydroxide (MM = 74) are 0,054 mol, since for solid reactants n= g/(MM) 20 ml of nitric acid 6 M are 0,12 mol, since for solutionsn=M xx V= 6 (mol)/L xx 0,020 L=0,12 mol then you …

23.36 ml is required. H_2SO_ (4 (aq))+2NaOH_ ( (aq))rarrNa_2SO_ (4 (aq))+2H_2O_ ( (l)) c=n/v So n = cv So we can get the no. moles of H_2SO_4: n = 0.102xx (15)/ (1000)=1.53xx10^ (-3)mol From the …

So, the problem provides you with n, V, and T, and asks you to find the value of P, the pressure of the gas. What you need to do now is isolate P on one side of the ideal gas law equation by dividing both …

"3.1 mol L"^(-1) The idea here is that the volume of the solution will decrease, but that the number of moles of sodium hydroxide, "NaOH", will remain unchanged. Since molarity is defined as number of …

From this we find: V prop T V prop n Thus, PV prop nT, and the constant of proportionality is R, the universal gas constant, so PV = nRT is the ideal gas law, where: P is the pressure in "atm" if R = …

Simply put, the number of moles of sulfuric acid that took part in the reaction is equal to the number of moles of hydrogen gas produced by the reaction. n_ (H_2SO_4) = n_ (H_2) = "0.6605 moles" …

You'd need 67 g of potassium nitrate to make that respective solution. Molarity is defined as moles of solute, in your case potassium nitrate, per liters of solution. Since you know the volume of the final …

V total = V acetic ac. +V N aOH V total = 25.00 + 20.00 = 45.00 mL and contain 0.0025 moles of acetate ions, which were porduced by the neutralization reaction in accordance to the 1:1 mole ratio that …