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  1. Solution to IMO 2023 Problem 1 - Mathematics Stack Exchange

    Aug 8, 2023 · Here's the details of the problem: Problem 1. Determine all composite integers $n>1$ that satisfy the following properties: if $d_1, d_2,\cdot \cdot \cdot ,d_k$ are all the positive divisors of...

  2. Proofs are given when appropriate, or when they illustrate some insight or important idea. The problems are culled from various sources, many from actual contests and olympiads, and in general are very …

  3. 11.1: Divisibility Properties of Integers Prime Numbers and Composites De nition: If p is an integer greater than 1, then p is a prime number if the only divisors of p are 1 and p. De nition: A positive …

  4. Prime Divisors Theorem 1. If n > 1 is composite, then n has a prime. divisor. p such that p2 n. Remark. Another p way to say this is that a composite integer n > 1 has p a. prime divisor p with p n. So if an …

  5. Fermat's Little Theorem: Let p be a prime. Then ap 1 d p) for any integer a not divisible by p. Euler's Theorem: Let n be a positive integer. Then (n) a 1 (mod n) integer a elat

  6. Wilson's Theorem | Brilliant Math & Science Wiki

    Wilson's theorem states that. a positive integer n> 1 n> 1 is a prime if and only if (n 1)! ≡ 1 (m o d n) (n− 1)! ≡ −1 (mod n). In other words, (n 1)! (n−1)! is 1 less than a multiple of n n. This is useful in …

  7. find all a,n >= 1 so that for all primes $p$ dividing $a^n-1 ...

    Dec 3, 2022 · You're correct that with a = 1 a = 1, then all n ≥ 2 n ≥ 2 works. However, regarding always requiring n ≥ 2 n ≥ 2, note there's one case where n = 1 n = 1 also works.